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Roulette table double zero

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I’d also like to add that what I have detailed above would work for literally ANY isolated Roulette bet, provided: You asked me not to attempt to do this until Wizard posts in this thread, so I won’t. The Binomial Distribution calculator can give you the probability of losing x or more where x is one more than half of all attempts.

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If you lose more trials than you win, then you are down money. The Wizard answered my PM indicating that there is a way to figure this out although there may not be a handy formulaįor this one, you could either use the Beating Bonuses simulator or a binomial distribution calculator the fact that these are flat bets at Even Money makes this quite easy to do if you are specifying a particular number of trials. If a player flat bets any even chance (one unit on one even chance) - what is the probability he will be down after a certain number of spins in double zero RouletteĪfter 1,000 spins - 98% probability the player will be downĪfter 600 spins - 92% probability the player will be downĪfter 100 spins - 80% probability the player will be downīut I don't know how to do the math to figure this out correctly Please don't attempt an answer until after the Wizard has posted The question has not been considered here (to my knowledge) or anywhere else that I know about By PM I posed a question to the Wizard and he indicated if I posted it he would respond

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